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A137156 Matrix inverse of triangle A137153(n,k) = C(2^k+n-k-1, n-k), read by rows. +0
7
1, -1, 1, 1, -2, 1, -2, 5, -4, 1, 9, -24, 22, -8, 1, -88, 239, -228, 92, -16, 1, 1802, -4920, 4749, -1976, 376, -32, 1, -75598, 206727, -200240, 84086, -16432, 1520, -64, 1, 6421599, -17568408, 17034964, -7173240, 1413084, -133984, 6112, -128, 1 (list; table; graph; listen)
OFFSET

0,5

COMMENT

Unsigned column 0 = A001192, number of full sets of size n.

FORMULA

G.f. of column k: 1 = Sum_{n>=0} T(n+k,k)*x^n/(1-x)^(2^(n+k)).

EXAMPLE

Triangle begins:

1;

-1, 1;

1, -2, 1;

-2, 5, -4, 1;

9, -24, 22, -8, 1;

-88, 239, -228, 92, -16, 1;

1802, -4920, 4749, -1976, 376, -32, 1;

-75598, 206727, -200240, 84086, -16432, 1520, -64, 1;

6421599, -17568408, 17034964, -7173240, 1413084, -133984, 6112, -128, 1; ...

PROGRAM

(PARI) /* As matrix inverse of A137153: */ {T(n, k)=local(M=matrix(n+1, n+1, r, c, if(r>=c, binomial(2^(c-1)+r-c-1, r-c)))); if(n<k|k<0, 0, (M^-1)[n+1, k+1]} (PARI) /* Using the g.f.: */ {T(n, k)=if(n<k|k<0, 0, if(n==k, 1, polcoeff(1-sum(j=0, n-k-1, T(j+k, k)*x^j/(1-x+x*O(x^(n-k)))^(2^(j+k))), n-k)))}

CROSSREFS

Cf. A137153 (matrix inverse); unsigned columns: A001192, A137157, A137158, A137159; unsigned row sums: A137160.

Adjacent sequences: A137153 A137154 A137155 this_sequence A137157 A137158 A137159

Sequence in context: A099602 A104560 A121435 this_sequence A136457 A078016 A078046

KEYWORD

sign,tabl

AUTHOR

Paul D. Hanna (pauldhanna(AT)juno.com), Jan 24 2008

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Last modified January 7 17:35 EST 2009. Contains 152824 sequences.


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