|
Search: id:A137470
|
|
|
| A137470 |
|
Inverse binomial transform of 1, 2, 2, 4, 10, 20, ... = A100088. |
|
+0
1
|
|
| 1, 1, -1, 3, -1, -1, 7, -9, 7, 7, -25, 39, -25, -25, 103, -153, 103, 103, -409, 615, -409, -409, 1639, -2457, 1639, 1639, -6553, 9831, -6553, -6553, 26215, -39321, 26215, 26215, -104857, 157287, -104857, -104857, 419431
(list; graph; listen)
|
|
|
OFFSET
|
0,4
|
|
|
FORMULA
|
a(n)=[3+(1-2I)(I-1)^n+(1+2I)(-1-I)^n]/5 where I=sqrt(-1). - R. J. Mathar (mathar(AT)strw.leidenuniv.nl), Apr 25 2008
O.g.f.: -(1+2x)/((1+2x+2x^2)(-1+x)). - R. J. Mathar (mathar(AT)strw.leidenuniv.nl), Apr 25 2008
a(n+1)-a(n)=A090132(n+1). - R. J. Mathar (mathar(AT)strw.leidenuniv.nl), Apr 25 2008
|
|
CROSSREFS
|
Adjacent sequences: A137467 A137468 A137469 this_sequence A137471 A137472 A137473
Sequence in context: A057004 A059328 A075440 this_sequence A112492 A049290 A134567
|
|
KEYWORD
|
sign
|
|
AUTHOR
|
Paul Curtz (bpcrtz(AT)free.fr), Apr 20 2008
|
|
EXTENSIONS
|
More terms from R. J. Mathar (mathar(AT)strw.leidenuniv.nl), Apr 25 2008
|
|
|
Search completed in 0.002 seconds
|
