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Array begins:
m/n|3.4.5..6..7..8...9..10...11...12....13....14.....15.....16.....17......18
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1..|1.2.5.13.33.89.240.657.1806.5026.13999.39260.110381.311465.880840.2497405
2..|.......1..2..8..23..74..220..674..2011..6038..17980..53547.158907..471225
3..|.................1...2....8...27....89...289....938...2985...9456...29722
4..|...............................1.....2.....8.....27.....94....309....1035
5..|..................................................1......2......8......27
6..|........................................................................1
-----------------------------------------------------------------------------
m/n|.....19.......20.......21........22........23.........24.........25....
---------------------------------------------------------------------------
1..|7093751.20187313.57537552.164235501.469406091.1343268050.3848223585....
2..|1394786..4124929.12185636..35972082.106111713..312835608..921809509....
3..|..92842...288509...892506...2749940...8443504...25845735...78897469....
4..|...3382....11040....35659....114614....365970....1163167....3678680....
5..|.....94......315.....1060......3507.....11570......37853.....123196....
6..|......2........8.......27........94.......315.......1067.......3537....
7..|........................1.........2.........8.........27.........94....
8..|.......................................................1..........2....
9..|.......................................................................
The first row is A001429. Sums of columns form A137917.
Both the 5th and the 6th rows of table T begin with the same values, 1, 2, 8, 27, 94, and 315.
This happen since the number of graphs with n vertices and m components is equal to the number of graphs with n+3j vertices and m+j components, n >=3, j >= 1.
So T(5,16) = T(6,19), T(5,17) = T(6,20), T(5,18) = T(6,21) etc.
In the sequence A138386 one can see the first terms of the m-th row of table T as m tends to infinity.
Parts equal to 3 do not change the values taken by the product in the formula since if i = 3, C(f(i) + K_i - 1, K_i) = C(1 + K_i - 1, Ki) = 1.
Because of that we take i >= 4 in the formula.
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