1,2

A131383(n) = sum of n-th row;

A000027(n) = T(n,1);

A000120(n) = T(n,2) for n>1;

A053735(n) = T(n,3) for n>2;

A053737(n) = T(n,4) for n>3;

A053824(n) = T(n,5) for n>4;

A053827(n) = T(n,6) for n>5;

A053828(n) = T(n,7) for n>6;

A053829(n) = T(n,8) for n>7;

A053830(n) = T(n,9) for n>8;

A007953(n) = T(n,10) for n>9;

A053831(n) = T(n,11) for n>10;

A053832(n) = T(n,12) for n>11;

A053833(n) = T(n,13) for n>12;

A053834(n) = T(n,14) for n>13;

A053835(n) = T(n,15) for n>14;

A053836(n) = T(n,16) for n>15;

A007395(n) = T(n,n-1) for n>1;

A000012(n) = T(n,n).

Eric Weisstein's World of Mathematics, Digit Sum

Start of the triangle for n in base k representation:

......................1

....................11....10

......... ........111....11...10

................1111...100...11..10

..............11111...101...12..11..10

............111111...110...20..12..11..10

..........1111111...111...21..13..12..11..10

........11111111..1000...22..20..13..12..11..10

......111111111..1001..100..21..14..13..12..11..10

....1111111111..1010..101..22..20..14..13..12..11..10

..11111111111..1011..102..23..21..15..14..13..12..11..10

111111111111..1100..110..30..22..20..15..14..13..12..11..10,

and the triangle of sums of digits starts:

......................1

.....................2...1

......... ..........3...2...1

...................4...1...2...1

..................5...2...3...2...1

.................6...2...2...3...2...1

................7...3...3...4...3...2...1

...............8...1...4...2...4...3...2...1

..............9...2...1...3...5...4...3...2...1

............10...2...2...4...2...5...4...3...2...1

...........11...3...3...5...3...6...5...4...3...2...1

..........12...2...2...3...4...2...6...5...4...3...2...1.

Adjacent sequences: A138527 A138528 A138529 this_sequence A138531 A138532 A138533

Sequence in context: A086414 A098896 A108371 this_sequence A002341 A128260 A083368

nonn,base,tabl

Reinhard Zumkeller (reinhard.zumkeller(AT)gmail.com), Mar 26 2008