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A138750 a(n)=ceil(n/2) if n=2 (mod 3), a(n)=2n else. +0
8
0, 2, 1, 6, 8, 3, 12, 14, 4, 18, 20, 6, 24, 26, 7, 30, 32, 9, 36, 38, 10, 42, 44, 12, 48, 50, 13, 54, 56, 15, 60, 62, 16, 66, 68, 18, 72, 74, 19, 78, 80, 21, 84, 86, 22, 90, 92, 24, 96, 98, 25, 102, 104, 27, 108, 110, 28, 114, 116, 30, 120, 122, 31, 126, 128, 33, 132, 134, 34 (list; graph; listen)
OFFSET

0,2

COMMENT

This map is inspired by A124123, which hides in

fact a variation of the Collatz problem,

defined on the set of primes, and working mod 3 instead of mod 2. See

A138751 for more information.

The use of ceil() is here equivalent to round().

The main reason for defining this function is to write A124123 as

complement of A007918( A138750( A000040 )),

and to express the recursion function occurring there in terms of this map.

It might have been more natural to define this map as a(n)=2n if n=1

(mod 3), a(n)=ceil(n/2) else,

which is equivalent for all primes > 3 (which are either =1 or =2

(mod 3)) and would have "better"

properties regarding the analysis of orbits of all integers under this map.

However, for the prime n=3 it does make a difference,

and in order to reproduce the map occurring in A124123, we had to

adopt the present convention.

LINKS

Georges Brougnard, Definition of GB-sequences.

Index entries for sequences related to 3x+1 (or Collatz) problem

EXAMPLE

a(0)=2*0=0, a(1)=2*1=2, a(3)=2*3=6, a(4)=2*4=8,... since

these indices are not equal to 2 (mod 3).

a(2)=ceil(2/2)=1, a(5)=ceil(5/2)=3, a(8)=ceil(8/2)=4,

a(11)=ceil(11/2)=6,... since these indices equal 2 (mod 3).

PROGRAM

(PARI) A138750(n) = if( n%3==2, ceil(n/2), 2*n )

CROSSREFS

Cf. A001281, A124123, A138751-A138753.

Adjacent sequences: A138747 A138748 A138749 this_sequence A138751 A138752 A138753

Sequence in context: A138510 A026215 A026220 this_sequence A048850 A004488 A011419

KEYWORD

easy,nonn

AUTHOR

M. F. Hasler (www.univ-ag.fr/~mhasler), Mar 28 2008

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Last modified October 6 16:13 EDT 2008. Contains 144667 sequences.


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