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Search: id:A138912
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| 1, 1, 2, 9, 28, 145, 726, 4249, 27000, 186561, 1387450, 11034001, 93295236, 834720913, 7870851366, 77943848025, 808159323376, 8749874083585, 98687599614450, 1157060036429857, 14075106913366140, 177337182574590801
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OFFSET
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0,3
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COMMENT
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The n-th term of the n-th inverse binomial transform of A138911 is 1 for n>=0.
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FORMULA
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O.g.f. satisfies: [x^n] A( x/(1+(n-1)*x) )/(1+(n-1)*x) = 1 for n>=0.
E.g.f. satisfies: [x^n] A(x)*exp(-(n-1)*x) = 1/n! for n>=0.
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PROGRAM
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(PARI) {a(n)=local(A=[1]); for(k=1, n, A=concat(A, 0); A[k+1]=1-polcoeff(subst(Ser(A), x, x/(1+(k-1)*x+x*O(x^k)))/(1+(k-1)*x), k)); A[n+1]}
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CROSSREFS
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Cf. A138911 (binomial transform).
Sequence in context: A002532 A098518 A086511 this_sequence A002747 A110377 A041877
Adjacent sequences: A138909 A138910 A138911 this_sequence A138913 A138914 A138915
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KEYWORD
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nonn
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AUTHOR
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Paul D. Hanna (pauldhanna(AT)juno.com), Apr 05 2008
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