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Search: id:A140946
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| A140946 |
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Jacobsthal via Jacobsthal (*). Consider today b(n)=0, 1, 0, -1, 2, 0, 3, -2, 4, 0 . a(n)=b(n+1)-2b(n). Terms n(n+3)/2 (A000096): 1, -1, 3 =A001045(n+1) signed, between which are -2; 4, -4; -8, 8, -8; see A140513 "signed". Compare to a sequence in A140589 comment. |
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+0
1
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| 1, -2, -1, 4, -4, 3, -8, 8, -8, -5, 16, -16, 16, -16, 11, -32, 32, -32, 32, -32, -21
(list; graph; listen)
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OFFSET
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0,2
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COMMENT
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(*) Second part on three. Maybe four. a(n) with,from -2, not repeated 2^n = 1, -2, -1, 4, 3, -8, -5, 16, 11 ; unsigned = A112387.
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CROSSREFS
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Sequence in context: A101621 A086484 A091335 this_sequence A008741 A110316 A111975
Adjacent sequences: A140943 A140944 A140945 this_sequence A140947 A140948 A140949
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KEYWORD
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sign,uned
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AUTHOR
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Paul Curtz (bpcrtz(AT)free.fr), Jul 24 2008
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