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Search: id:A141430
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| A141430 |
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(A000111,full Euler numbers) mod 9. Also from A004099. After 1, 1 , period 12: 1, 2, 5, 7, 7, 2, 8, 7, 4, 2, 2, 7 (*) . |
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+0
3
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| 1, 1, 1, 2, 5, 7, 7, 2, 8, 7, 4, 2, 2, 7, 1, 2, 5, 7, 7, 2, 8, 7, 4, 2, 2, 7, 1, 2, 5, 7, 7, 2, 8, 7, 4, 2, 2, 7, 1, 2, 5, 7, 7, 2, 8, 7, 4, 2, 2, 7
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OFFSET
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0,4
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COMMENT
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(*) This period 12 is mix A070366, A010697; a(n+2)+a(n+8)= 9, 9, 9, 9, 9, 9, 9, 9, 9 =A010734 .See also period 10 A140684 (0, 1, 6, 5). a(n+13-p)-a(n+2+p)= period 6:repeat 6, 0, -3, -3, 0, 6 (p=0 to 5).
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FORMULA
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a(n) has only digits 1, 2, 4, 5, 7, 8. See today period 6: 1, 2, 4, 5, 7, 8. Period contains ordered 1, 2, 2, 2, 2, 4, 5, 7, 7, 7, 7, 8 ,also linked to A010734.
a(n)=(1/132)*{9*(n mod 12)+31*[(n+1) mod 12]+42*[(n+2) mod 12]+20*[(n+3) mod 12]-57*[(n+4) mod 12]+64*[(n+5) mod 12]+9*[(n+6) mod 12]-13*[(n+7) mod 12]-24*[(n+8) mod 12]-2*[(n+9) mod 12]+75*[(n+10) mod 12]-46*[(n+11) mod 12]}-[C(2*n,n) mod 2]-6*{C[(n+1)^2,n+3] mod 2} [From Paolo P. Lava (ppl(AT)spl.at), Aug 25 2008]
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CROSSREFS
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Sequence in context: A079378 A066035 A078320 this_sequence A021392 A131688 A096624
Adjacent sequences: A141427 A141428 A141429 this_sequence A141431 A141432 A141433
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KEYWORD
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nonn,uned
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AUTHOR
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Paul Curtz (bpcrtz(AT)free.fr), Aug 06 2008
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