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Search: id:A141465
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| A141465 |
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Primes of the transform ((p(max)-1)*..*p*(p(min)-2)), where (p(max))*..*p*(p(min)=k(n)=n-th composite. |
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+0 1
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| 2, 3, 2, 5, 3, 11, 17, 29, 41, 59, 71, 101, 107, 137, 149, 179, 191, 197, 227, 239, 269, 281, 311, 347, 419, 431, 461, 521, 569, 599, 617, 641, 659, 809, 821, 827, 857, 881, 1019, 1031, 1049, 1061, 1091, 1151, 1229, 1277, 1289, 1301, 1319, 1427, 1451, 1481
(list; graph; listen)
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OFFSET
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1,1
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EXAMPLE
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If k(1)=4=(p(max)=2)*(p(min)=2), then (2-2)*(2-1)=0*1=0
(nonprime).
If k(2)=6=(p(max)=3)*(p(min)=2), then
(3-2)*(2-1)=1*1=1 (nonprime).
If k(3)=8=(p(max)=2)*(p=2)*(p(min)=2), then
(2-2)*2*(2-1)=0*2*1=0 (nonprime).
If k(4)=9=(p(max)=3)*(p(min)=3), then
(3-2)*(3-1)=1*2=2=a(1).
If k(5)=10=(p(max)=5)*(p(min)=2), then
(5-2)*(2-1)=3*1=3=a(2).
If k(6)=12=(p(max)=3)*(p=2)*(p(min)=2), then
(3-2)*2*(2-1)=1*2*1=2=a(3).
If k(7)=14=(p(max)=7)*(p(min)=2), then
(7-2)*(2-1)=5*1=5=a(4).
If k(8)=15=(p(max)=5)*(p(min)=3), then
(5-2)*(3-1)=3*2=6 (composite),
If k(9)=16=(p(max)=2)*2*2*(p(min)=2), then
(2-2)*2*2*(2-1)=0*2*2*1=0 (nonprime).
If k(10)=18=(p(max)=3)*(p=3)*(p(min)=2), then
(3-2)*3*(2-1)=1*3*1=3=a(5), etc.
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CROSSREFS
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Sequence in context: A075105 A094020 A165609 this_sequence A141663 A011153 A132226
Adjacent sequences: A141462 A141463 A141464 this_sequence A141466 A141467 A141468
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KEYWORD
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nonn,uned
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AUTHOR
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Juri-Stepan Gerasimov (2stepan(AT)rambler.ru) Aug 08 2008
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