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Search: id:A141530
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| A141530 |
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Third from a recurrences family concerning numerators of a(i,j) square defined by j!*a(i,j)=Integral (from i to i+1) u*(u-1)*(-2)* .. *(u-j+1) du. For recurrences,family begins at j=1 (not 0,hence third of the family instead of fourth). j=1: a(n)=a(n-1)+2 ,A005408; j=2: a(n)=2a(n-1)-a(n-2)+12 ,A140811; j=3: a(n)=3a(n-1)-3a(n-2)+a(n-3)+24, this sequence; j=4: 4a(n-1)-6a(n-2)+4a(n-3)-a(n-4)+720; j=5: 5a(n-1)-10a(n-2)+10a(n-3)-5a(n-4)+a(n-5)+1440; then Pascal A007318 without first 1's, signed, followed with A0911317(j). A091137(j) is ALSO a(i,j) denominators, not A002790 as written in A140825 modified Aug 6. |
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