|
Search: id:A143132
|
|
|
| A143132 |
|
Binomial transform of [1, 5, 15, 35, 70, 0, 0, 0,...]. |
|
+0
1
|
|
| 1, 6, 26, 96, 321, 876, 2006, 4026, 7321, 12346, 19626, 29756, 43401, 61296, 84246, 113126, 148881, 192526, 245146, 307896, 382001, 468756, 569526, 685746, 818921, 970626, 1142506, 1336276, 1553721, 1796696, 2067126, 2367006, 2698401, 3063446
(list; graph; listen)
|
|
|
OFFSET
|
1,2
|
|
|
COMMENT
|
Conjecture: rightmost digit of terms is cyclic: (1, 6, 6, 6,...repeat).
|
|
FORMULA
|
Binomial transform of [1, 5, 15, 35, 70, 0, 0, 0,...] where (1, 5, 15, 35, 70) = row 4 of triangle A046899.
O.g.f.: (1+x+6x^2+16x^3+46x^4)/(1-x)^5. a(n)=46-200*n+330*A000217(n)-245*A000292(n)+70*A000332(n+3). [From R. J. Mathar (mathar(AT)strw.leidenuniv.nl), Jul 31 2008]
a(n) = (552 - 1190 n + 895 n^2 - 280 n^3 + 35 n^4)/12 [From T. D. Noe (noe(AT)sspectra.com), Aug 22 2008]
|
|
EXAMPLE
|
a(4) = 96 = (1, 3, 3, 1) dot (1, 5, 15, 35) = (1 + 15 + 45 + 35).
|
|
CROSSREFS
|
Cf. A046899.
Adjacent sequences: A143129 A143130 A143131 this_sequence A143133 A143134 A143135
Sequence in context: A036645 A000393 A106392 this_sequence A055589 A055420 A137746
|
|
KEYWORD
|
nonn
|
|
AUTHOR
|
Gary W. Adamson (qntmpkt(AT)yahoo.com), Jul 27 2008
|
|
EXTENSIONS
|
More terms from T. D. Noe (noe(AT)sspectra.com), Aug 22 2008
|
|
|
Search completed in 0.002 seconds
|
