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A143409 Square array read by antidiagonals: form the Euler-Seidel matrix for the sequence {k!} and then divide column k by k!. +0
5
1, 2, 1, 5, 3, 1, 16, 11, 4, 1, 65, 49, 19, 5, 1, 326, 261, 106, 29, 6, 1, 1957, 1631, 685, 193, 41, 7, 1, 13700, 11743, 5056, 1457, 316, 55, 8, 1, 109601, 95901, 42079, 12341, 2721, 481, 71, 9, 1, 986410, 876809, 390454, 116125, 25946, 4645, 694, 89, 10, 1 (list; table; graph; listen)
OFFSET

0,2

COMMENT

The Euler-Seidel matrix for the sequence {k!} is array A076571 read as a square, whose k_th column entries have a common factor of k!. Removing these common factors gives the current table. This table is closely connected to the constant 1/e. The row, column and diagonal entries of this table occur in series acceleration formulas for 1/e. For a similar table based on the differences of the sequence {k!} and related to the constant e, see A086764. For other arrays similarly related to constants see A143410 (for sqrt(e)), A143411 (for 1/sqrt(e)), A008288 (for log(2)), A108625 (for zeta(2)) and A143007 (for zeta(3)).

LINKS

D. Dumont, Matrices d'Euler-Seidel, Sem. Loth. Comb. B05c (1981) 59-78.

Eric Weisstein's World of Mathematics Poisson-Charlier polynomial

FORMULA

T(n,k) = 1/k!*sum {j = 0..n} C(n,j)*(k+j)!. T(n,k) = (n+k)!/k!*Num_Pade(n,k), where Num_Pade(n,k) denotes the numerator of the Pade approximation for the function exp(x) of degree (n,k) evaluated at x = 1. Recurrence relations: T(n,k) = T(n-1,k) + (k+1)*T(n-1,k+1); T(n,k) = (n+k)*T(n-1,k) + T(n-1,k-1). E.g.f for column k: exp(y)/(1-y)^(k+1). E.g.f. for array: exp(y)/(1-x-y) = (1 + x + x^2 + ...) + (2 + 3*x + 4*x^2 + ...)*y + (5 + 11*x + 19*x^2 + ...)*y^2/2! + ... . Row n lists the values of the Poisson-Charlier polynomial x^(n) + C(n,1)*x^(n-1) + C(n,2)*x^(n-2) + ... + C(n,n) for x = 1,2,3,..., where x^(m) denotes the rising factorial x*(x+1)*...*(x+m-1). Main diagonal is A001517. Series formulas for 1/e: Row n: 1/e = n!*[1/T(n,0) - 1/(1!*T(n,0)*T(n,1)) + 1/(2!*T(n,1)*T(n,2)) - 1/(3!*T(n,2)*T(n,3)) + ...]. Column k: k!/e = A000166(k) + (-1)^(k+1)*[0!/(T(0,k)*T(1,k)) + 1!/(T(1,k)*T(2,k)) + 2!/(T(2,k)*T(3,k)) + ...]. Main diagonal: 1/e = 1 - 2* sum {n = 0..inf} (-1)^n/(T(n,n)*T(n+1,n+1)) = 1 - 2*[1/(1*3) - 1/(3*19) + 1/(19*193) - ...]. Second subdiagonal: 1/e = 2*[1^2/(1*5) - 2^2/(5*49) + 3^2/(49*685) - ...]. Compare with A143413.

EXAMPLE

The Euler-Seidel matrix for the sequence {k!} begins

==============================================

n\k|.....0.....1.....2.....3.....4.....5.....6

==============================================

0..|.....1.....1.....2.....6....24...120...720

1..|.....2.....3.....8....30...144...840

2..|.....5....11....38...174...984

3..|....16....49...212..1158

4..|....65...261..1370

5..|...326..1631

6..|..1957

...

Dividing the k_th column by k! gives

==============================================

n\k|.....0.....1.....2.....3.....4.....5.....6

==============================================

0..|.....1.....1.....1.....1.....1.....1.....1

1..|.....2.....3.....4.....5.....6.....7

2..|.....5....11....19....29....41

3..|....16....49...106...193

4..|....65...261...685

5..|...326..1631

6..|..1957

...

Examples of series formula for 1/e:

Row 2: 1/e = 2*[1/5 - 1/(1!*5*11) + 1/(2!*11*19) - 1/(3!*19*29) + ...].

Column 4: 24/e = 9 - [0!/(1*6) + 1!/(6*41) + 2!/(41*316) + ...].

MAPLE

with combinat: T := (n, k) -> 1/k!*add(binomial(n, j)*(k+j)!, j = 0..n): for n from 0 to 9 do seq(T(n, k), k = 0..9) end do;

CROSSREFS

Cf. A008288, A076571, A086764, A108625, A143007, A143410, A143411, A143413, A001517 (main diagonal), A028387 (row 2), A000522 (column 0), A001339 (column 1), A082030 (column 2), A095000 (column 3), A095177 (column 4).

Sequence in context: A048471 A067345 A160185 this_sequence A067418 A067323 A106534

Adjacent sequences: A143406 A143407 A143408 this_sequence A143410 A143411 A143412

KEYWORD

easy,nonn,tabl

AUTHOR

Peter Bala (pbala(AT)toucansurf.com), Aug 14 2008

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Last modified November 25 20:09 EST 2009. Contains 167514 sequences.


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