0,3

Period 12: a(n+12)=a(n).

Sums of periodic trisections: a(3n)+a(3n+3)+a(3n+6)+a(3n+9) = a(3n+1)+a(3n+4)+a(3n+7)+a(3n+10) = a(3n+2)+a(3n+5)+a(3n+8)+a(3n+11) = 16.

a(n)=(1/132)*{8*(n mod 12)+74*[(n+1) mod 12]-47*[(n+2) mod 12]+96*[(n+3) mod 12]+8*[(n+4) mod 12]-25*[(n+5) mod 12]-36*[(n+6) mod 12]-14*[(n+7) mod 12]+107*[(n+8) mod 12]-36*[(n+9) mod 12]-36*[(n+10) mod 12]-3*[(n+11) mod 12]}, with n>=0 [From Paolo P. Lava (ppl(AT)spl.at), Oct 22 2008]

G.f.: x(6x^7-5x^6+8x^5+6x^4-8x^3+4x^2+4x+1)/((1-x)(1+x)(x^2+1)(x^2-x+1)(x^4-x^2+1)). - R. J. Mathar (mathar(AT)strw.leidenuniv.nl), Dec 02 2008

Sequence in context: A046490 A155214 A028934 this_sequence A019636 A102521 A096789

Adjacent sequences: A144405 A144406 A144407 this_sequence A144409 A144410 A144411

nonn

Paul Curtz (bpcrtz(AT)free.fr), Sep 30 2008

Edited by R. J. Mathar (mathar(AT)strw.leidenuniv.nl), Dec 02 2008