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Search: id:A144449
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OFFSET
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1,1
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COMMENT
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Multiples of 8; a(n)mod9=period 3:repeat 7,4,1=A070403(n+1). From Paschen spectrum of hydrogen.
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FORMULA
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(A061039(6n+2)=A061039(6n-4)+24*(3n+1)=a(6n-4)+72n+24,a(2)=16). a(n)=a(n-1)+24*(3n+1)=a(n-1)+72n+24, a(0)=16.
a(n)=4*(4+9*n^2+15*n), with n>=0 [From Paolo P. Lava (ppl(AT)spl.at), Oct 28 2008]
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CROSSREFS
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Adjacent sequences: A144446 A144447 A144448 this_sequence A144450 A144451 A144452
Sequence in context: A120668 A053526 A107908 this_sequence A000143 A035016 A081194
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KEYWORD
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nonn,uned
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AUTHOR
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Paul Curtz (bpcrtz(AT)free.fr), Oct 06 2008
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