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Search: id:A144458
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| A144458 |
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Two sequence determinant triangle sequence: a(n)=A000045(n); b(n)=b(n-1)+b(n-2)+b(n-3) :2 start;A141036(n); t(n,m)=t(n,m)=a(m)*b(n)-b(m)*a(n). |
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+0 1
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| -2, -2, 0, -4, 2, 2, -6, 3, 3, 0, -10, 6, 6, 2, 3, -16, 13, 13, 10, 15, 17, -26, 25, 25, 24, 36, 47, 31, -42, 49, 49, 56, 84, 119, 119, 112, -68, 95, 95, 122, 183, 271, 318, 385, 329, -110, 182, 182, 254, 381, 580, 741, 991, 1127, 963
(list; graph; listen)
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OFFSET
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1,1
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COMMENT
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Row sums are:{-2, -2, 0, 0, 7, 52, 162, 546, 1730, 5291}.
Reasoning behind the sequence is:
Suppose we have n affine transforms that form a group:
g={ a(1)*x+b(1),a(2)*x+b(2),...,a(n)*x+b(n)}
on the sequences a(n) and b(n).
We form rational projections as Moebius / bilinear transforms:
g(projection)={( a(1)*x+b(1))/(a(n)*x+b(n)),( a(2)*x+b(2))/(a(n)*x+b(n)),...,( a(n-1)*x+b(n-1))/(a(n)*x+b(n))
With determinants:
g_det={a(1)*b(n)-b(1)*a(n),a(2)*b(n)-b(2)*a(n),...,a(n-1)*b(n)-b(n-1)*a(n)}
So that we have the triangular sequences:
t(n,m)=a(m)*b(n)-b(m)*a(n)
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FORMULA
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a(n)=A000045(n); b(n)=b(n-1)+b(n-2)+b(n-3) :2 start;A141036; t(n,m)=t(n,m)=a(m)*b(n)-b(m)*a(n).
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EXAMPLE
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{-2},
{-2, 0},
{-4, 2, 2},
{-6, 3, 3, 0},
{-10, 6, 6, 2, 3},
{-16, 13, 13, 10, 15, 17},
{-26, 25, 25, 24, 36, 47, 31},
{-42, 49, 49, 56, 84, 119, 119, 112},
{-68, 95, 95, 122, 183, 271, 318, 385, 329},
{-110, 182, 182, 254, 381, 580, 741, 991, 1127, 963}
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MATHEMATICA
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Clear[a, b, t, n, m] a[n_] := Fibonacci[n]; b[0] = 2; b[1] = 1; b[2] = 1; b[n_] := b[n] = b[n - 1] + b[n - 2] + b[n - 3]; t[n_, m_] := a[m]*b[n] - b[m]*a[n]; Table[Table[t[n, m], {m, 0, n - 1}], {n, 1, 10}]; Flatten[%]
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CROSSREFS
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Cf. A141036, A000045.
Sequence in context: A138094 A060821 A005881 this_sequence A098268 A128585 A141333
Adjacent sequences: A144455 A144456 A144457 this_sequence A144459 A144460 A144461
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KEYWORD
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uned,sign
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AUTHOR
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Roger L. Bagula and Gary W. Adamson (rlbagulatftn(AT)yahoo.com), Oct 07 2008
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