1,2

On the odd and even indices respectively the same recurrence is obtained :a(n+2)=1154*a(n+1)-a(n)-192. we have also : a(n+2)=577*a(n+1)-96+68*(72*a(n)^2-24*a(n)-32)^0.5

a(1)=1 because 6*1-1=5 is A144796(1)

Cf. A133301, A144796, A144797

Sequence in context: A004329 A089909 A049434 this_sequence A036084 A004338 A014772

Adjacent sequences: A144938 A144939 A144940 this_sequence A144942 A144943 A144944

easy,nonn

Richard Choulet (richardchoulet(AT)yahoo.fr), Sep 26 2008