1,1

General formula for a(n+1)=a(n)^2+2*a(n)-2 and a(1)=k+1 is a(n)=Floor[((k + Sqrt[k^2 + 4])/2)^(2^((n+1) - 1))

aa = {}; k = 5; Do[AppendTo[aa, k]; k = k^2 + 2 k - 2, {n, 1, 10}]; aa

or

k =4; Table[Floor[((k + Sqrt[k^2 + 4])/2)^(2^(n - 1))], {n, 2, 7}] (*Artur Jasinski*)

A145502-A145511

Sequence in context: A087618 A134152 A140424 this_sequence A124936 A068560 A039773

Adjacent sequences: A145502 A145503 A145504 this_sequence A145506 A145507 A145508

nonn

Artur Jasinski (grafix(AT)csl.pl), Oct 11 2008