1,1

General formula for a(n+1)=a(n)^2+2*a(n)-2 and a(1)=k+1 is a(n)=Floor[((k + Sqrt[k^2 + 4])/2)^(2^((n+1) - 1))

aa = {}; k = 10; Do[AppendTo[aa, k]; k = k^2 + 2 k - 2, {n, 1, 10}]; aa

or

k =9; Table[Floor[((k + Sqrt[k^2 + 4])/2)^(2^(n - 1))], {n, 2, 7}] (*Artur Jasinski*)

A145502-A145511

Sequence in context: A024129 A155622 A122887 this_sequence A024128 A030022 A069673

Adjacent sequences: A145507 A145508 A145509 this_sequence A145511 A145512 A145513

nonn

Artur Jasinski (grafix(AT)csl.pl), Oct 11 2008