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Search: id:A145530
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| A145530 |
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Numbers x such that there exists n in N with (x+1)^3-x^3=91*n^2 |
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+0
1
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| 5, 8002, 11635629, 16918197290, 24599047224757, 35766997746600114, 52005190124509341725, 75615510674038836268762, 109944900514862343425438949, 159859809733099173301751963810
(list; graph; listen)
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OFFSET
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1,1
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FORMULA
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a(n+2)=1454*a(n+1)-a(n)+726
a(n)=-(1/2)+(11/4)*{[727-44*sqrt(273)]^n+[727+44*sqrt(273)]^n}-(1/6)*sqrt(273)*{[727-44 *sqrt(273)]^n-[727+44*sqrt(273)]^n}, with n>=0 [From Paolo P. Lava (ppl(AT)spl.at), Nov 25 2008]
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EXAMPLE
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a(1)=5 because the first relation is (5+1)^3-5^3=91*1^2
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CROSSREFS
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Sequence in context: A137694 A117711 A116140 this_sequence A067816 A076629 A052027
Adjacent sequences: A145527 A145528 A145529 this_sequence A145531 A145532 A145533
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KEYWORD
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easy,nonn
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AUTHOR
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Richard Choulet (richardchoulet(AT)yahoo.fr), Oct 12 2008, Oct 13 2008
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