Logo

Greetings from The On-Line Encyclopedia of Integer Sequences!

Hints

Search: id:A145883
Displaying 1-1 of 1 results found. page 1
     Format: long | short | internal | text      Sort: relevance | references | number      Highlight: on | off
A145883 Triangle read by rows: T(n,k) is the number of odd permutations of {1,2,...,n} having k descents. (n>=1, k>=1). +0
2
0, 1, 2, 1, 6, 6, 12, 36, 12, 28, 155, 147, 29, 1, 56, 605, 1208, 586, 64, 1, 120, 2160, 7800, 7800, 2160, 120, 240, 7320, 44160, 78000, 44160, 7320, 240, 496, 23947, 227623, 655039, 655315, 227569, 23893, 517, 1, 992, 76305, 1102068, 4868556 (list; graph; listen)
OFFSET

1,3

COMMENT

Number of entries in row n is ceil(C(n,2)/2) - ceil(C(n-2,2/2).

Sum of entries in row n is A001710(n) for n>=2.

REFERENCES

R. P. Stanley, Binomial posets, Moebius inversion and permutation enumeration, J. Combinat. Theory, A 20 (1976), 336-356.

J. Shareshian and M. L. Wachs, q-Eulerian polynomials: excedance number and major index, Electronic Research Announcements of the Amer. Math. Soc., 13 (2007), 33-45.

S. Tanimoto, A study of Eulerian numbers for permutations in the alternating group, Integers, Electronic J. of Combinatorial Number Theory, 6 (2006), #A31.

FORMULA

In the Shareshian and Wachs reference (p. 35) a q-analog of the exponential g.f. of the Eulerian polynomials is given for the joint distribution of (inv, des) (see also the Stanley reference). The Maple program given below makes use of this function by considering its odd part.

EXAMPLE

T(4,2)=6 because we have 1432, 3142, 3214, 4312, 4231 and 3421.

Triangle starts:

0;

1;

2,1;

6,6;

12,36,12;

28,155,147,29,1;

MAPLE

for n to 11 do qbr := proc (m) options operator, arrow; sum(q^i, i = 0 .. m-1) end proc; qfac := proc (m) options operator, arrow; product(qbr(j), j = 1 .. m) end proc; Exp := proc (z) options operator, arrow; sum(q^binomial(m, 2)*z^m/qfac(m), m = 0 .. 19) end proc; g := (1-t)/(Exp(z*(t-1))-t); gser := simplify(series(g, z = 0, 17)); a[n] := simplify(qfac(n)*coeff(gser, z, n)); b[n] := (a[n]-subs(q = -q, a[n]))*1/2; P[n] := sort(subs(q = 1, b[n])) end do; 0; for n to 11 do seq(coeff(P[n], t, j), j = 1 .. ceil((1/2)*binomial(n, 2))-ceil((1/2)*binomial(n-2, 2))) end do; # yields sequence in triangular form

CROSSREFS

A001710, A145882

Sequence in context: A117965 A111646 A117753 this_sequence A062820 A113336 A113979

Adjacent sequences: A145880 A145881 A145882 this_sequence A145884 A145885 A145886

KEYWORD

nonn,tabf

AUTHOR

Emeric Deutsch (deutsch(AT)duke.poly.edu), Nov 11 2008

page 1

Search completed in 0.002 seconds

Lookup | Welcome | Find friends | Music | Plot 2 | Demos | Index | Browse | More | WebCam
Contribute new seq. or comment | Format | Transforms | Puzzles | Hot | Classics
More pages | Superseeker | Maintained by N. J. A. Sloane (njas@research.att.com)

Last modified November 29 12:46 EST 2009. Contains 167659 sequences.


AT&T Labs Research