|
Search: id:A146291
|
|
|
| A146291 |
|
Triangle T(n,m) read by rows (n >= 1, 0 <= m <= A001222(n)), giving the number of divisors of n with m prime factors (counted with multiplicity). |
|
+0 4
|
|
| 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 2, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 2, 1, 1, 1, 1, 2, 2, 1, 1, 1, 1, 2, 1, 1, 2, 1, 1, 1, 1, 1, 1, 1, 1, 1, 2, 2, 1, 1, 1, 1, 2, 2, 1, 1, 2, 1, 1, 2, 1, 1, 1, 1, 2, 2, 2, 1, 1, 1, 1, 1, 2, 1, 1, 1, 1, 1, 1, 2, 2, 1, 1, 1, 1, 3, 3, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 2, 1, 1, 2, 1, 1, 2
(list; graph; listen)
|
|
|
OFFSET
|
1,12
|
|
|
COMMENT
|
All rows are palindromic. (n,0)=(n, A001222(n))=1.
Two numbers have identical rows in the table if and only if they have the same prime signature.
|
|
LINKS
|
Anonymous?, Polynomial calculator
Eric Weisstein's World of Mathematics, Roundness
G. Xiao, WIMS server, Factoris (both expands and factors polynomials)
|
|
FORMULA
|
If the canonical factorization of n into prime powers is the product of p^e(p), then T(n, m) is the coefficient of k^m in the polynomial expansion of Product_p (sum_{i=0..e} k^i).
|
|
EXAMPLE
|
Rows begin: 1; 1,1; 1,1; 1,1,1; 1,1; 1,2,1; 1,1; 1,1,1,1; 1,1,1; 1,2,1;...
12 has 1 divisor with 0 total prime factors (1), 2 with 1 (2 and 3), 2 with 2 (4 and 6) and 1 with 3 (12), for a total of 6. The 12th row of the table therefore reads (1, 2, 2, 1). These are the positive coefficients of the polynomial 1 + 2k + 2k^2 + (1)k^3 = (1 + k + k^2)(1 + k), derived from the prime factorization of 12 (namely, 2^2*3^1).
|
|
CROSSREFS
|
Row sums equal A000005(n). (n, 1)= A001221(n) for n>1.
Row n of A007318 is identical to row A002110(n) of this table and also identical to the row for any squarefree number with n prime factors.
Cf. A146292. Also cf. A146289, A146290.
Sequence in context: A043287 A043286 A043285 this_sequence A086251 A092931 A147300
Adjacent sequences: A146288 A146289 A146290 this_sequence A146292 A146293 A146294
|
|
KEYWORD
|
nonn,tabf
|
|
AUTHOR
|
Matthew Vandermast (ghodges14(AT)comcast.net), Nov 11 2008
|
|
|
Search completed in 0.002 seconds
|