0,2

A regular version of Pitoun's sequence: a(n)=A029898(n+1).

Also obtained from permutations of A141425, A020806, A070366, A153110, A153990, A154127, A154687, or A154815.

The sequence and the (again 6-period) repeated differences build the table

..1,..2,..4,..8,..7,..5,..1,..2,..4,..8,..7,...

..1,..2,..4,.-1,.-2,.-4,..1,..2,..4,.-1,.-2,...

..1,..2,.-5,.-1,.-2,..5,..1,..2,.-5,.-1,.-2,...

..1,.-7,..4,.-1,..7,.-4,..1,.-7,..4,.-1,..7,...

.-8,.11,.-5,..8,-11,..5,.-8,.11,.-5,..8,-11,...

.19,-16,.13,-19,.16,-13,.19,-16,.13,-19,.16,...

-35,.29,-32,.35,-29,.32,-35,.29,-32,.35,-29,...

.64,-61,.67,-64,.61,-67,.64,-61,.67,-64,.61,...

If each entry of this table is read modulo 9 we obtain the very regular table

..1,..2,..4,..8,..7,..5,..1,..2,..4,..8,..7,...

..1,..2,..4,..8,..7,..5,..1,..2,..4,..8,..7,...

..1,..2,..4,..8,..7,..5,..1,..2,..4,..8,..7,...

..1,..2,..4,..8,..7,..5,..1,..2,..4,..8,..7,...

..1,..2,..4,..8,..7,..5,..1,..2,..4,..8,..7,...

..1,..2,..4,..8,..7,..5,..1,..2,..4,..8,..7,...

Also the decimal expansion of the constant 125/1001. [R. J. Mathar (mathar(AT)strw.leidenuniv.nl), Jan 23 2009]

Terms of the simple continued fraction of 254/(sqrt(548587)-565). [From Paolo P. Lava (ppl(AT)spl.at), Feb 17 2009]

a(n)=(1/30)*{29*(n mod 6)+19*[(n+1) mod 6]+14*[(n+2) mod 6]-11*[(n+3) mod 6]-[(n+4) mod 6]+4*[(n+5) mod 6], with n>=0 [From Paolo P. Lava (ppl(AT)spl.at), Dec 19 2008]

a(n)+a(n+3) = 9 = A010734(n).

G.f.: (1+x+2x^2+5x^3)/((1-x)(1+x)(1-x+x^2)). [R. J. Mathar (mathar(AT)strw.leidenuniv.nl), Jan 23 2009]

a(n) = A082365(n) mod 9. [Paul Curtz (bpcrtz(AT)free.fr), Mar 31 2009]

Sequence in context: A061284 A016017 A071571 this_sequence A029898 A021406 A065075

Adjacent sequences: A153127 A153128 A153129 this_sequence A153131 A153132 A153133

nonn,easy

Paul Curtz (bpcrtz(AT)free.fr), Dec 19 2008

Edited by R. J. Mathar (mathar(AT)strw.leidenuniv.nl), Apr 09 2009