0,3

The sequence can be obtained by re-ordering A000290 and deleting squares of the form A130824(k)^2.

Denominator of 1/4-1/(2n)^2, if n>0.

a(2n+1) = A016754(n). a(2n) = 16*A000290(n).

a(n) = A061038(2*n) (bisection).

a(n) = 3*a(n-2)-3*a(n-4)+a(n-6). G.f.: x*(1+16*x+6*x^2+16*x^3+x^4)/((1-x)^3*(1+x)^3).

Sequence in context: A070567 A070688 A103167 this_sequence A040242 A070578 A028695

Adjacent sequences: A154612 A154613 A154614 this_sequence A154616 A154617 A154618

nonn,easy

Paul Curtz (bpcrtz(AT)free.fr), Jan 13 2009

Edited, offset set to 1, and extended by R. J. Mathar (mathar(AT)strw.leidenuniv.nl), Sep 07 2009

a(0) added Oct 21 2009