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FORMULA
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The n(j) recurrence is n(1)=0 ; n(2)=120 ; n(3)=899*n(2) ; n(t+3)=899*(n(t+2)-n(t+1)) + n(t) ;
resulting in n(j) terms 0, 120, 107880, 96876240, 86994755760 as listed above
The a(j) recurrence is a(1)=1 ; a(2)=29 ; a(t+2)=30*a(t+1)-a(t) ;
resulting in a(j) terms 1,29, 869, 26041, 780361, 23384789, 700763309
The b(j) recurrence is b(1)=1 ; b(2)=31; b(t+2)=30*b(t+1)-b(t);
resulting in b(j) terms 1, 31, 929, 27839, 834241
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