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Search: id:A158109
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| A158109 |
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G.f.: A(x) = exp(Sum_{n>=1} C(2n-1,n)*L(n)*x^n/n) such that Sum_{n>=1} L(n)*x^n/n = log(1+x*A(x)) where L(n) = A158259(n) and C(2n-1,n) = A001700(n-1). |
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2
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| 1, 1, 2, 15, 479, 58981, 27087299, 46407723445, 298505825690021, 7255847001783419768, 670260315103084510835973, 236409648316126537191063108559, 319643614642063671478190549232176669
(list; graph; listen)
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OFFSET
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0,3
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EXAMPLE
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G.f.: A(x) = 1 + x + 2*x^2 + 15*x^3 + 479*x^4 + 58981*x^5 +...
log(1+x*A(x)) = x + 1*x^2/2 + 4*x^3/3 + 53*x^4/4 + 2321*x^5/5 +...
log(A(x)) = x + 3*x^2/2 + 40*x^3/3 + 1855*x^4/4 + 292446*x^5/5 +...
log(A(x)) = x + 3*1*x^2/2 + 10*4*x^3/3 + 35*53*x^4/4 + 126*2321*x^5/5 +...
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PROGRAM
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(PARI) {a(n)=local(A=1+x); if(n==0, 1, for(i=1, n, A=exp(sum(m=1, n, binomial(2*m-1, m)*x^m*polcoeff(log(1+x*A+x*O(x^m)), m))+x*O(x^n))); polcoeff(A, n))}
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CROSSREFS
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Cf. A158259, A158257 (variant), A001700.
Sequence in context: A012943 A013059 A013098 this_sequence A136463 A078475 A015185
Adjacent sequences: A158106 A158107 A158108 this_sequence A158110 A158111 A158112
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KEYWORD
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nonn
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AUTHOR
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Paul D. Hanna (pauldhanna(AT)juno.com), Mar 28 2009
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