1,2

The a(j) recurrence is a(1)=1; a(2)=23; a(t+2)=24*a(t+1)-a(t)

resulting in terms 1, 23, 551, 13201

The b(j) recurrence is b(1)=1; b(2)=25; b(t+2)=24*b(t+1)-b(t)

resulting in terms 1, 25, 599, 14351.

The n(j) recurrence is n(0)=n(1)=1; n(2)=48; n(t+3)=575*(n(t+2)-n(t+1))+n(t)

resulting in terms 0, 0, 48, 27600, 15842400 as listed above.

for a from 1 by 2 to 100000 do b:=sqrt((13*a*a-2)/11): if (trunc(b)=b) then

n:=(a*a-1)/11: La:=[op(La), a]:Lb:=[op(Lb), b]:Ln:=[op(Ln), n]: endif: enddo:

A157456

Sequence in context: A130417 A123478 A159425 this_sequence A164278 A159441 A011787

Adjacent sequences: A159662 A159663 A159664 this_sequence A159666 A159667 A159668

nonn

Paul Weisenhorn (paulweisenhorn(AT)online.de), Apr 19 2009