1,2

The a(j) recurrence is a(1)=1; a(2)=27; a(t+2)=28*a(t+1)-a(t)

resulting in terms 1, 27, 755, 21113 as listed above

The b(j) recurrence is b(1)=1; b(2)=29; b(t+2)=28*b(t+1)-b(t)

resulting in terms 1, 29, 811, 22679.

The n(j) recurrence is n(0)=n(1)=0; n(2)=56; n(t+3)=783*(n(t+2)-n(t+1))+n(t)

resulting in terms 0, 0, 56, 43848, 34289136.

for a from 1 by 2 to 100000 do b:=sqrt((15*a*a-2)/13): if (trunc(b)=b) then

n:=(a*a-1)/13: La:=[op(La), a]:Lb:=[op(Lb), b]:Ln:=[op(Ln), n]: endif: enddo:

A157456

Sequence in context: A009971 A046240 A042406 this_sequence A158645 A138979 A159234

Adjacent sequences: A159665 A159666 A159667 this_sequence A159669 A159670 A159671

nonn

Paul Weisenhorn (paulweisenhorn(AT)online.de), Apr 19 2009