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Search: id:A159922
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| A159922 |
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Least index m such that the five numbers 2*prime(m+k)+3^n, k=0 to 4, are five consecutive primes. |
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| 643266, 8813528, 1644953, 440421, 2826655, 1339785, 2775232, 988180, 196973, 643136, 4122122, 3477939, 182124, 6195602, 130854, 4937610, 2725523
(list; graph; listen)
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OFFSET
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1,1
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FORMULA
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a(1)=A102810(1) = A102811(5) = A089009(11). - R. J. Mathar (mathar(AT)strw.leidenuniv.nl), Apr 28 2009
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EXAMPLE
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For n=15, prime(m=130854)=1739401 starts the prime sequence 1739401, 1739411, 1739417, 1739443, 1739447 of five consecutive primes.
With 3^n=3^15=14348907, the five numbers 17827709=2*1739401+14348907, 17827729=2*1739411+14348907, 17827741=2*1739417+14348907, 17827793=2*1739443+14348907, 17827801=2*1739447+14348907 are consecutive primes, and m=130854 is the smallest prime index of this kind, so a(n=15)=130854.
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CROSSREFS
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Sequence in context: A089220 A052243 A102810 this_sequence A154873 A061406 A034628
Adjacent sequences: A159919 A159920 A159921 this_sequence A159923 A159924 A159925
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KEYWORD
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nonn
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AUTHOR
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Pierre CAMI (pierre-cami(AT)orange.fr), Apr 26 2009
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EXTENSIONS
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Edited by R. J. Mathar (mathar(AT)strw.leidenuniv.nl), Apr 28 2009
Replaced the wrong value 14348916 by 14348907 (3^15=14348907). - Pierre CAMI (pierre-cami(AT)orange.fr), May 09 2009
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