|
Search: id:A159938
|
|
|
| A159938 |
|
The number of homogeneous trisubstituted linear alkanes. |
|
+0 1
|
| |
|
|
OFFSET
|
2,1
|
|
|
COMMENT
|
See the paper by Valentin Vankov Iliev for details.
|
|
REFERENCES
|
Valentin Vankov Iliev, "A mathematical characterization of the groups of substitution isomerism of the linear alkanes", J. Math. Chem., 45 (2009), xxx-yyy. Page numbers unknown as of today as it is an 'online first' article.
|
|
FORMULA
|
a(n) = (1/3) (2 n^3 - 9 n^2 + 19 n - 12) where n is the number of carbons.
a(n)= 2*A081489(n-1) = (n-1)(2n^2-7n+12)/3. [From R. J. Mathar (mathar(AT)strw.leidenuniv.nl), Apr 28 2009]
|
|
EXAMPLE
|
The number of homogeneous trisubstituted linear alkane with ten carbon atoms is 426.
|
|
CROSSREFS
|
A002522, A033816
Sequence in context: A032091 A060354 A140131 this_sequence A145126 A005676 A038503
Adjacent sequences: A159935 A159936 A159937 this_sequence A159939 A159940 A159941
|
|
KEYWORD
|
nonn
|
|
AUTHOR
|
Parthasarathy Nambi (PachaNambi(AT)yahoo.com), Apr 26 2009
|
|
|
Search completed in 0.002 seconds
|