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A160456 Number of triangles that can be built from rods with lengths 1,2,...,n by using and concatenating not necessarily all rods. +0
1
0, 3, 20, 70, 172, 366, 709, 1274, 2166, 3537, 5573, 8494, 12588, 18227, 25846, 35942, 49124, 66138, 87827, 115132, 149166, 191238, 242800, 305447, 381012, 471602, 579518, 707254, 857627, 1033812, 1239238, 1477589, 1752963 (list; graph; listen)
OFFSET

3,2

COMMENT

a(n) is the number of triples (a,b,c) with b+c > a >= b >=c > 0 such that three disjoint subsets A,B,C of {1,2,...,n} with respective element sums a,b,c exist.

LINKS

H. v. Eitzen, Table of n, a(n) for n=3..5262 (i.e. a(n) less than 2^64)

"AI", (Sci.math thread)

H. v. Eitzen, How to Build Triangles from Integers

FORMULA

If n<=2, then trivially a(n)=0 because three edges need at least three rods.

If n>=8 then a(n) = A001400(n*(n+1)/2 - 3) - 11 - A133872(n+1).

EXAMPLE

For n = 4, there are 10 triangles with perimeter at most 1+2+3+4 = 10: (1,1,1), (2,2,1), (2,2,2), (3,2,2), (3,3,2), (3,3,3), (4,3,2), (4,3,3), (4,4,1) and (4,4,2). We have a(4)=3 because only 3 of these can be built from rods among 1,2,3,4: (4,3,2), (4,3,3)=(4,3,1+2) and (4,4,2)=(4,1+3,2). For exammple, it is not possible to build (4,4,1) because the 1-rod must be used for one of the 4-edges.

CROSSREFS

A002623 is a similar problem where one rod per edge is to be used.

A160455 is a similar problem where all rods must be used.

A160438 is related to this if one drops the triangle inequality condition.

Sequence in context: A099721 A024402 A067600 this_sequence A006411 A129549 A092786

Adjacent sequences: A160453 A160454 A160455 this_sequence A160457 A160458 A160459

KEYWORD

easy,nonn

AUTHOR

Hagen von Eitzen (math(AT)von-eitzen.de), May 14 2009

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Last modified November 24 23:16 EST 2009. Contains 167481 sequences.


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