0,2

n^2=m^3+(m+1)^3+(m+2)^3 =3*(1 + m)*(3 + 2*m + m^2),

n = 0, 3, 6, 204 for m = -1, 0, 1, 23.

Sequence in context: A074880 A115647 A019437 this_sequence A083149 A068375 A126297

Adjacent sequences: A163420 A163421 A163422 this_sequence A163424 A163425 A163426

fini,full,nonn

Zak Seidov (zakseidov(AT)yahoo.com), Jul 27 2009