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Search: id:A163824
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| A163824 |
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Sum of first n terms equals n-th number of set (1, primes). |
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+0
1
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| 1, 1, 1, 2, 2, 4, 2, 4, 2, 4, 6, 2, 6, 4, 2, 4, 6, 6, 2, 6, 4, 2, 6, 4, 6, 8, 4, 2, 4, 2, 4, 14, 4, 6, 2, 10, 2, 6, 6, 4, 6, 6, 2, 10, 2, 4, 2, 12, 12, 4
(list; graph; listen)
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OFFSET
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1,4
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COMMENT
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a(n) = inverse of partial sums of set (1, primes). Inverse of partial sums (IPS) of sequence b(n) is sequence c(n): c(1) = b(1); c(n) = b(n) - b(n-1) for n >= 2, i.e. first diferences of sequence b(n) for for n >= 2. a(n) = IPS(A158611(n)) for n >= 1 = IPS(A008578(n-1)) for n >= 1 = IPS(IPS(A014284(n))) for n >= 1 = IPS(IPS(IPS(A023538(n))) for n >= 1. a(1) = 1, a(n) = A075526(n-2) for n >= 2. a(1) = 1, a(2) = 1, a(n) = A001223(n-2) for n >= 3. Partial sums of sequence a(n) are sequences A158611(n) and A008578(n-1) for n >= 1.
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CROSSREFS
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Sequence in context: A040003 A106469 A082508 this_sequence A075526 A001223 A118776
Adjacent sequences: A163821 A163822 A163823 this_sequence A163825 A163826 A163827
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KEYWORD
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nonn
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AUTHOR
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Jaroslav Krizek (jaroslav.krizek(AT)atlas.cz), Aug 04 2009, Aug 06 2009
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