|
Search: id:A164131
|
|
|
| A164131 |
|
Numbers n such that n^2 ==2 (mod 31). |
|
+0 1
|
|
| 8, 23, 39, 54, 70, 85, 101, 116, 132, 147, 163, 178, 194, 209, 225, 240, 256, 271, 287, 302, 318, 333, 349, 364, 380, 395, 411, 426, 442, 457, 473, 488, 504, 519, 535, 550, 566, 581, 597, 612, 628, 643, 659, 674, 690, 705, 721, 736, 752, 767, 783, 798, 814
(list; graph; listen)
|
|
|
OFFSET
|
1,1
|
|
|
COMMENT
|
Sequences of the type n^2 == 2 (mod m) are basically defined for each m of A057126. See A047341 (m=7), A113804 (m=14), A155449 (m=17), A155450 (m=23), A158803 (m=41) etc. [R. J. Mathar, Aug 26 2009]
|
|
LINKS
|
Index to sequences with linear recurrences with constant coefficients, signature (1,1,-1)
|
|
FORMULA
|
a(n) = a(n-1)+a(n-2)-a(n-3).
a(n) = (31+(-1)^(n-1)+62(n-1))/4.
G.f.: x*(8+15*x+8*x^2)/((1+x)*(x-1)^2). [R. J. Mathar, Aug 26 2009]
Except for the first term, a(n)=31*n-a(n-1), (with a(1)=23) [From Vincenzo Librandi (vincenzo.librandi(AT)tin.it), Oct 23 2009]
|
|
EXAMPLE
|
At n= 4, a(4)= (31-1+186)/4=54. At n=5, a(5)=(31+1+248)/4=70.
|
|
CROSSREFS
|
Sequence in context: A003342 A164284 A047719 this_sequence A114381 A139433 A033951
Adjacent sequences: A164128 A164129 A164130 this_sequence A164132 A164133 A164134
|
|
KEYWORD
|
nonn
|
|
AUTHOR
|
Vincenzo Librandi (vincenzo.librandi(AT)tin.it), Aug 11 2009
|
|
EXTENSIONS
|
Entries checked by R. J. Mathar (mathar(AT)strw.leidenuniv.nl), Aug 26 2009
Deleted an 8 in an A-number of the comment - R. J. Mathar (mathar(AT)strw.leidenuniv.nl), Aug 27 2009
|
|
|
Search completed in 0.002 seconds
|