id:A166407 - OEIS Search Results

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a(n) = floor(3*(A166406(n)/A005408(n))).

+0
3

-3, 1, 0, 3, -9, 3, 0, 6, 0, 3, 0, 9, -30, 1, 0, 9, 0, 6, 0, 12, 0, 3, 0, 15, -63, 6, 0, 12, 0, 9, 0, 6, 0, 3, 0, 21, 0, 2, 0, 15, -81, 9, 0, 18, 0, 6, 0, 24, 0, 0, 0, 15, 0, 9, 0, 24, 0, 6, 0, 30, -165, 6, 0, 15, 0, 15, 0, 6, 0, 9, 0, 30, 0, 0, 0, 21, 0, 12, 0, 30, 0, 3, 0, 33, -234, 6, 0, 6 (list; graph; listen)

	OFFSET	`0,1`
	COMMENT	`Conjecture: the quotient A166406(i)/A005408(i) has denominator 3 when i is one of the terms of A166101, and it is integral in other cases. If true, then floor in the formula is unnecessary.`
	LINKS	`A. Karttunen, Table of n, a(n) for n = 0..65535`
	CROSSREFS	`Cf. A166408.` `Sequence in context: A122016 A067882 A110033 this_sequence A159059 A127569 A117372` `Adjacent sequences: A166404 A166405 A166406 this_sequence A166408 A166409 A166410`
	KEYWORD	`sign`
	AUTHOR	`Antti Karttunen (His-Firstname.His-Surname(AT)gmail.com), Oct 21 2009`

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Last modified December 1 19:22 EST 2009. Contains 167811 sequences.

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